How do I prove that a = v * dv/dx? My book says that a =dv/dt = dv/dx * dx/dt = dv/dx * v That looks all ok but according to this equation it seems that x(displacement) is a function of t whereas x=v * t. So how can we differentiate x without differentiating v which leads to circular reasoning?
you do have a point, but if we replace backwards. i.e, we write x as function of v rather than v as function of x, it wouldn't be right. x and t are the final or say independent variables here . So, if a term comes dx/dt ,we simply write it = v instead of putting x = v*t . And , the more important fact is that in this case, x is not equal to simply v*t , instead., dx = vdt
basically, the glitch is : assuming x = vt
I guess we are getting somewhere..... equation in the book: dv/dt = dv/dx * dx/dt .....(1) According to it,it seems like t is the only independent variable and not x! Heres my thinking: v=w o u (v is a composite function) x=u(t) => dx/dt v=w(x) => dv/dx so dv/dt = dx/dt * dv/dx and so we get equation (1) I want you to tell me that is my process right or i am mistaken. Also my conclusion is that t is the only independent variable here. Am i right?
there is more of differential calculus here, than simply functions . If y = f(x) and x = g(t) , then while differentiating y with respect to x, we can use the given function of x and can go a step forward and find the result in t-derivative.
maybe, I'm unable to explain this, but I can tell you for sure, it's not simply multiplying dv/dx and dx/dt ,
what is your real question here. lets discuss it the not calculus way if thats what your looking for.
x is not displacement x is position :P v= dx/dt is the rate of change of position..
correct mashy. don't forget that acceleration is the slope of velocity vector if you use the graphical analysis approach
The above equation mentioned in the question is perfect.. and ll tell you when to use it if your velocity function is given in terms of displacement.. for example v(x) = 3x (m/s) then find the acceleration at x = 2 m so we can do a = dv/dx times v = 3 *2 = 6m/s^2
m sorry that is 3*6= 18m/s^2 :D
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