Question

N

Answer 1

ok what is it

Answer 2

im sorry cant see that

Answer 3

So the first one says
1/cot^2 x + secx.cosx.
WE know that secx = 1/cos x thus the second part is = 1
and we know that 1/cot^2 x = tan^2 x
Thus the answer is tan^2 x + 1 which is the same as sec^2 x [BASIC IDENTITY]
So the answer is D) sec^2 x

Answer 4

OK

Answer 5

I hope this helped :)

Answer 6

OH CAN YOU SOLVE ONE MORE THING PLEASE FORGOT TO ADD IT

Answer 7

Factor the algebraic expression below in terms of a single trigonometric function.

csc 2x - 1

Answer 8

cosec 2x - 1 = 1/sin2 x - 1
which can also be written as (1-sin 2 x)/sin 2 x
And we know that 1 - sin 2 x = cos 2 x
Thus the answer is cos 2 x/sin 2 x = which is the same as cot 2 x :)
I hope this helped! :)

Answer 9

THANKS SOO MUCHH!!