A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the water rises part-way along the straight sides, and then
5.00 cm3 of oil is poured into one end. As a result, the top surface of the oil ends up 0.550 cm higher than the water surface on the other side of the U. What is the density of the oil?
Answer: _______ kg/m3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
the density of oil is less than the density of water
OpenStudy (summersnow8):
5.39d
OpenStudy (shamim):
pressure of both sides r equal
OpenStudy (shamim):
i know thr density of water is 1gm/cm^3
OpenStudy (summersnow8):
well it is 1000kg/m^3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
1000kg/m^3=1000*1000gm/10^6cm^3
OpenStudy (shamim):
=1gm/cm^3
OpenStudy (summersnow8):
okay, but we are looking for kg/m3
OpenStudy (summersnow8):
is this right?
5-0.550=4.45
5cm^3 of oil=4.45cm^3 of water
density of oil=4.45/5=0.89 of water
0.89*1000=890km/m^3
OpenStudy (summersnow8):
@shamim
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
ya i think ur result is ok
OpenStudy (summersnow8):
so its 890kg/m^3
OpenStudy (shamim):
in my equation h= height of water
OpenStudy (summersnow8):
okay, so you believe that mine is correct? did you get the same as me?
OpenStudy (shamim):
h*1*9.8=(h-4.45)*1*9.8+5*d*9.8
h=height of water level
g=9.8 m/sec^2
1gm/cm^3 is the density of watet
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
ya my result will b same as u
OpenStudy (shamim):
but my result is in cgs system
we hv to convert it into mks system
OpenStudy (shamim):
just multiply by 1000
OpenStudy (shamim):
did u get my solution
OpenStudy (summersnow8):
hmm i dont understand how you solved it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
i think mine is better for understanding
OpenStudy (summersnow8):
well can you show me the equation then show me the numbers plugged in, im really confused
OpenStudy (shamim):
ok
OpenStudy (shamim):
c my equation
OpenStudy (shamim):
u know the pressure of both sides r equal
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
one side is full of water
OpenStudy (shamim):
let the height of that water is h
OpenStudy (shamim):
other side is full of water n oil
OpenStudy (shamim):
water height is less than the water height of other side by 4.45cm
OpenStudy (shamim):
height of oil is 5 cm
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (summersnow8):
im way confused :/
OpenStudy (shamim):
u know the equation of pressure is
p=hdg
h=height of liquid
d=density of lequid
g=9.8 m/sec^2
OpenStudy (shamim):
i hv to draw it for better understanding
OpenStudy (shamim):
i m now frm my cell phone
so its not possible to dtaw
OpenStudy (shamim):
draw
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (summersnow8):
but i am confused on what the value of h is and the density of the liquid....
OpenStudy (shamim):
i c
OpenStudy (shamim):
h will b cancell out
OpenStudy (shamim):
n we will find out the value of liquid d
OpenStudy (summersnow8):
okay, you have to write me the equation that gives me 890, because im not understanding how you got yours
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shamim):
u will take all h terms in one side
OpenStudy (shamim):
h*1*9.8=(h-4.45)*1*9.8+5*d*9.8
h=(h-4.45)+5*d
i cancelled 9.8 frm each term
OpenStudy (shamim):
5*d=h-h+4.45
OpenStudy (shamim):
5*d=4.45
OpenStudy (shamim):
did u get now
Still Need Help?
Join the QuestionCove community and study together with friends!