MEDAL AS A REWARD!!!

The area of a regular hexagon is 55 in.2 Find the length of a side. Round your answer to the nearest tenth.
I need help figuring out how to solve this!

Question

MEDAL AS A REWARD!!!   


   The area of a regular hexagon is 55 in.2 Find the length of a side. Round your answer to the nearest tenth.
I need help figuring out how to solve this!

dumbcow · Answer

use area formula for regular hexagon http://en.wikipedia.org/wiki/Hexagon#Regular_hexagon

anonymous · Answer

.................I still don't get it?

dumbcow · Answer

$$55 = \frac{3\sqrt{3}}{2}s^{2}$$

anonymous · Answer

.......

anonymous · Answer

I'm seriously stuck :C

dumbcow · Answer

are you having trouble using the formula? or are you trying to understand how to derive the formula

anonymous · Answer

both :'C

dumbcow · Answer

ok
|dw:1376433442881:dw|
hexagon has 6 equal triangles...find area of 1 triangle
|dw:1376433602962:dw|
from trig, tan 60 = sqrt3
tan = opp/adj = h/(x/2) = sqrt3
--> h = (sqrt3/2)x
Area of 1 triangle  = 1/2*x*h = (sqrt3/4)x^2

multiply by 6
--> Area = (3sqrt3/2)x^2

anonymous · Answer

So I'm basically working my way backwards.....okay