Question

what is the pattern between 13^1,13^2,13^3,13^4,13^5,13^6,13^7,...

Answer 1

*13

Answer 2

well yeah, but besides that?

Answer 3

because everytime you add ^1 youre multiplying it by 13

Answer 4

I know that....it's not the answer. Sorry I should've been more clear in the question. What do you notice in the pattern that is not multiplying by 13?

Answer 5

is it multiple choice

Answer 6

Negatory

Answer 7

i don't know then sorry

Answer 8

It's ok, thanks for trying!

Answer 9

Nvm

Answer 10

Hmm

Answer 11

@abb0t Hi!

Answer 12

*13, base case =13, recursive case= previous case * 13. adding previous number thirteen times, etc.. LOL thats about it, but it is all repeating * 13 process.

Answer 13

I was told that there is another pattern that is not the previous case being multiplied by; 13 or having anything to do with the number 13....I mentioned that earlier.

Answer 14

Apparently it has to do with the units in the answers of each individual number and the digits in the tens place?

Answer 15

It looks like you've two patterns, one where the base is consistently '13', and the second where the exponent is increased with '1'for every next step, so f(x) = a^x for x=[1,2,3,...]. This gives you the series 13 (x=1), 169 (x=2), 2197 (x=3) and on. Not sure if there is much more to make of this, unless you have additional information from the original quesion ?

Answer 16

It has nothing to do with the exponent or the base. I just asked and apparently it's a prelude to the question (13^12)^11

Answer 17

"First, though, lets try to solve a simpler problem, to find the units digit.

The way to go about it is to do some experiments.

Take a calculator and compute 13, 13^2, 13^3, 13^4 and so on. After you did about 10 of them see if you noticed something."

Answer 18

here is the series of pettern in sigma notation.