Question

Please help!
theta= pi/3
part 1: use the equations x=rcos(theta) and y=rsin(theta) to express x and y in terms of r. Two equations after this step.

part 2: Use the ratio (y/x) to find the slope of the line defined by this equation.

Answer 1

put the values.. That's it!

Answer 2

Thats what i was thinking it would be for part 1, so it would be x=rcos(pi/3) and y=rsin(pi/3), correct? I don't understand part 2, though.

Answer 3

http://www.mathsisfun.com/geometry/images/circle-unit-304560.gif
use this to find sin and cos of pi/3. and yes that is correct

Answer 4

For the second part do as suggested in question..
Divide y by x and substitute the values obtained in part one

Answer 5

is y=rsin(pi/3) = sqrt3/2 and x=rcos(pi/3)=1/2?

Answer 6

you forgot r

Answer 7

how do I find r?

Answer 8

you don't need to find..r will be cancelled out when you divide y by x

Answer 9

okay so if I did this correctly by dividing the two of them my answer would be sqrt3?

Answer 10

yep

Answer 11

Thanks soooo much! :)

Answer 12

@ujjwal oh wait, could you help me with one more thing please? :) How would I put this in slope-intercept form using the fact that it passes through the origin?

Answer 13

equation of a line passing through origin with slope m is given by
y=mx
where m is slope
second part gives you the value of slope, i.e. m
substitute value of m in y=mx
and that will be your answer

Answer 14

thanks again!