If the radius of A is units, and if triangle DGH and triangle DFE are isosceles right triangles with ED =DF=3 and DH=DG=6, approximate the area of the shaded region. (use pi=3.14)....
Choices:
A. 22.5
B.101
C.78.5
D.56
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
Hint:
Area of a Circle:
A = pi*r^2
r = radius
-----------------------------
Area of an Equilateral Triangle
A = s^2*sqrt(3)/4
s = side length of the triangle
OpenStudy (anonymous):
I ended up with 56
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what's the radius
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jimthompson5910 (jim_thompson5910):
that bit of info is missing
OpenStudy (anonymous):
The area of circle A = 25π
The area of ∆DFE = ½*3*3 = 9/2
The area of ∆DGH = ½*6*6 = 18
The shaded region is the area of the circle less the areas of the two triangles = 25π - 9/2 -18 = 56.04..... right?
jimthompson5910 (jim_thompson5910):
you're using the wrong formula to find the areas of the triangles