A certain keyboard has 5 more than twice as many keys across as it does vertically. The special keyboard has a total of 168 keys. ((((((Find the amount of keys positioned vertically and across)))))
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OpenStudy (anonymous):
168=(2a+5)??????????
OpenStudy (anonymous):
168=.5(a)(2a+5) ???????
jimthompson5910 (jim_thompson5910):
let x = # of keys across and y = # of keys vertically
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
"A certain keyboard has 5 more than twice as many keys across as it does vertically"
that all means
x = 2y + 5
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jimthompson5910 (jim_thompson5910):
The special keyboard has a total of 168 keys
tells us that
x*y = 168
OpenStudy (akashdeepdeb):
Multiply vertical with across = 168!
Gte quadratic equation solve it, then get the answer!
jimthompson5910 (jim_thompson5910):
x*y = 168
(2y + 5)*y = 168 ... plug in x = 2y + 5
2y^2 + 5y = 168
2y^2 + 5y - 168 = 0
I'll let you finish
OpenStudy (anonymous):
ummmm
OpenStudy (anonymous):
so we are = 0 right now
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jimthompson5910 (jim_thompson5910):
you now have to solve 2y^2 + 5y - 168 = 0 for y
jimthompson5910 (jim_thompson5910):
use the quadratic formula
OpenStudy (anonymous):
8??
jimthompson5910 (jim_thompson5910):
good y = 8, now use this to find x
OpenStudy (anonymous):
did you get across = 21
vertical = 8
????????
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