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solve for x: 8^x=5^(2x-1)
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1. take natural log of both sides
How would I take the natural log of 5^(2x-1)
ln(5^(2x-1)) = (2x-1)ln(5)
using law of logarithms
kk
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x(ln(8))=2x-1(ln(5))
right?
Good job
Next, I would divide by 2x-1?
And ln(8) on both sides?
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either way you do it, I am sure you will get the right answer.
I got ln(5/8)=x/2x-1
x/(2x-1)
What would I do from there?
try solving for x using proportion rules
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try it this way will be easier: \[x(\frac{ \ln8 }{ \ln5 })-2x+1=0\]
move everything to one side
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