Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − ___

Answer 1

x intercepts means y = 0.
So, when x = -8 or x = 2, y = 0. Then solve for the unknown constant

Answer 2

\[y = x^2 + 6x + 9 \rightarrow y = x^2 + 6x + 3^2\]

Answer 3

or \[y=x^2+6x+9→y=x^2+6x+(-3)^2\]

Answer 4

Thats wrong

Answer 5

ugh im so confused :(

Answer 6

What i meant is substitute x = 2 or x = -8(your choice) into the equation and y = 0. Then solve for the constant

Answer 7

so would it look like 0=-8^2+6(2)

Answer 8

right?

Answer 9

No

Answer 10

Just choose one x

Answer 11

can you show me?

Answer 12

0 = (2)^2 + 6(2) - __

Answer 13

Or
0 = (-8)^2 + 6(-8) - __
you will get the same answer

Answer 14

so how do i find the missing number?

Answer 15

0 = 2^2 + 6(2) - __
0 = 4 + 12 - __
16 - __ = 0
__ = 16

Answer 16

16?

Answer 17

Yes