Question

integrate with respect to x
(e^(2x)-e^(-2x)) /(e^(2x) +e^(-2x))

Answer 1

??????????/

Answer 2

well now i got it ur answer is wrong

Answer 3

i was thinking in any other way

Answer 4

e^(2x)-e^(-2x)
--------------
e^(2x) +e^(-2x)


e^(4x)-1
---------
e^(4x) +1

Answer 5

well there is a easy way than this one use subtitution XD directly XD

Answer 6

there usually is :) i like to algebra them a few times to see if theres a simpler form hidden inside

Answer 7

lol :P

Answer 8

me too was doing in the same way :P wasted so many hours

Answer 9

e^(4x)+1-2
----------
e^(4x) +1

\[1-\frac2{(e^{2x})^2+1}\] looks tangible ...

Answer 10

oh

Answer 11

u = e^2x; u' = 2 e^2x

but then again lol

Answer 12

hey i have one more question

Answer 13

:P

Answer 14

is it an easy one?

Answer 15

well i think so

Answer 16

integrate
1/[(sin(x-a)sin(x-b) ]

Answer 17

wrt x

Answer 18

i recall some trig stuff:

cos(a+b) = cosa cosb - sina sinb
-cos(a-b) = -cosa cosb - sina sinb
------------------------------

cos(a-b)/2 + cos(a+b)/2= sina sinb

Answer 19

oh oh but in book they have done it only in one way

Answer 20

let a = x-a, and b = x-b

a+b = 2x-(a+b)
a-b = b-a is a constant

Answer 21

\[\frac{2}{cos(2x-k)+n}\]

Answer 22

oh

Answer 23

with any luck, thats workable ....

Answer 24

oh :) tahnx :)

Answer 25

i wish if i could give u one more medal

Answer 26

thnx, but these are just some ideas, i do not know if they produce something simpler to play with or not :)

Answer 27

they will :P