A coin is flipped 8 times. Find the probability of the event: exactly 3 heads
@mebs
So your in data management right. Do you know any standard distribution?... here's how you do these questions.
(8 choose 3)(1/2)^3(1/2)^5
the probability of heads is 1/2 and so is tails so \[8C3(\frac{ 1 }{ 2 })^{3} (\frac{ 1 }{ 2 })^{5}\] the three represents the heads the other five must be the tails.
That would mean that if it rtossed thrice their can be 8 out comes (2^3) T T T H H H T T H H T H T H H H H T T H T H T T The probability of exactly 3 heads is = 1 possible out come/ 8 total outcomes = 1/8 Understood?
dude you missed so many outcomes....
the reason we just distribution patterns is not to do that kind of work.. though it is good to see it visually
Actually, I agree with @mebs @AkashdeepDeb assumes the person flipped three coins 8 times, which is not the scenario the question is referring to.
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