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∫sec(t/3)
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u substitution method. consider u=(t/3), then du= 1/3 dt
3integral(secudu)
simplify the expression..\[\int\limits_{?}^{?}\frac{ 1 }{ \cos(\frac{ t }{ 3 }) }dt\]
integral(secu)du= ln(|secu+tanu|)
than use u subtitution
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Aoi have you learned this integral yet? \(\large \int \sec x\;dx\) If not, we can do the necessary steps to solve this problem the long way. It's a little tricky though, and not intuitive at all. It's not a method you would just stumble upon.
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