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If f(x)=√x for x>0, then, for x>a>0, f(x)-f(a)/x-a=
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\[\frac{f(x)-f(a)}{x-a}=\frac{\sqrt x-\sqrt a}{x-a}\] Notice that the denominator can be written as a difference of squares: \[\frac{\sqrt x-\sqrt a}{x-a}=\frac{\sqrt x-\sqrt a}{\left(\sqrt x\right)^2-\left(\sqrt a\right)^2}=\frac{\sqrt x-\sqrt a}{\left(\sqrt x-\sqrt a\right)\left(\sqrt x+\sqrt a\right)}\] Which reduces to \[\frac{1}{\sqrt x+\sqrt a}\]
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