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Mathematics 21 Online
OpenStudy (anonymous):

f(x)=x+1/x Find all critical numbers. Find where the function is increasing and decreasing. Find critical points and identify each as a relative maximum, relative minimum, or neither. Find second order critical numbers and tell where the graph is concave up and where it is concave down.

OpenStudy (anonymous):

find the first derivative of the function to calculate the critical points and to find where the function is increasing and decreasing. then use the second derivative to find if the graph is concave up and where it is concave down.

OpenStudy (anonymous):

I know this but tell me how to trace the graph.

OpenStudy (anonymous):

The graph is a rectangular hyperbola. How to show this in written?

OpenStudy (anonymous):

i'm not sure how to show it in written.. but what i did when i'm solving this is first need to find the zeros of the first derivative and make a positive negative table and from there i can be able to tell if it is inreasing or decreasing then the second derivative i used to determine if it is concave up or concave down after all of this i will sketch the graph.. i'm not sure if this helps.. sorry

OpenStudy (anonymous):

The second derivative is 2/x^3. Now how to find whether it's concave up or concave down? I can't find the second order critical numbers because the term with x is in denominator.

OpenStudy (anonymous):

whats the first derivative?

OpenStudy (anonymous):

1-1/x^2

OpenStudy (anonymous):

it will be concave up if f"(x)>0, concave down if f"(x)<0

OpenStudy (anonymous):

Yes, right. But how to find second order critical numbers? I have to show the second order critical numbers also.

OpenStudy (anonymous):

wait..(still thinking) just give me a sec. i need to find my notes

OpenStudy (anonymous):

Okay! Take your time

OpenStudy (anonymous):

i'm just finished calculus, and i'm messing it up again..lol

OpenStudy (anonymous):

*I

OpenStudy (anonymous):

hahaha...

OpenStudy (anonymous):

The same happens with me also. Many times...

OpenStudy (anonymous):

Yes... then?

OpenStudy (anonymous):

.i don't know.. really sorry.. @Hero, @thomaster and @imranmeah91

OpenStudy (anonymous):

Okay... thanks for trying. :)

OpenStudy (joemc):

I doubt if this is going to be helpful. But, here is a plot of: the function f(x)=x+1/x http://fooplot.com/plot/hs8gcysc6e 1-1/x^2 http://fooplot.com/plot/s9uz9qnqhu 2/x^3 http://fooplot.com/plot/l7u7mzkpgz

OpenStudy (anonymous):

i have an idea,.!!!!!!! i said before that you can fin the critical points when f"(X)=undefined so:|dw:1376541687631:dw|

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