Question

Kinematics...
Relative Motion

Answer 1

My PMs are taking too long so I cant send PMs!!

Answer 2

Just hold on for a sec..

Answer 3

Ya Sure!!

Answer 4

I think it should be A

Answer 5

Do you have an answer key or something?

Answer 6

Answers are A and B...How ?? Pls xplain the process!!

Answer 7

YEah just wait a sec.

Answer 8

yup..Ta

Answer 9

Okay I got A n B
:D

Answer 10

I will try my best to explain it to you!
Just let me just draw it

Answer 11

Take ur time ..No rush

Answer 12

I am bit curious, do you have a test or something?

Answer 13

Nope just wanna finish this assignment .Have a deadline submission..........4 exercises+1 BIG assignment

Answer 14

This Q is from the exercise!!

Answer 15

Are u posting the picture?? Or Using Open study tools??

Answer 16

Now use the resultant vecotr formula that says that if
There are 2 vectors A and B and theta (here, 37') is included between them then
Their resultant's magnitude is given by
\[\sqrt(A^2 + B^2 + 2ABcos \theta)\]
And you will get something like
rt. 564.9 m/s.
Which is almost A :)
That is the magnitude of the resultant relative vector
Getting me? :D