Find the value of k so that the three points lie on the same line. Write the equation of the line in point-slope form. (1,-2) (-2,4) (4,k)
k= -8 y+8 = -2 (x - 4)
How did you come up with k=-8?
Can someone explain how to solve this?
Since all three points are on the same line, the slope of the segment connecting any two points will be the same. So, you know that \[\large\underbrace{\frac{4-(-2)}{-2-1}}_{\text{slope between first and second point}}=\underbrace{\frac{k-4}{4-(-2)}}_{\text{slope between second and third point}}\] Solve the equation for \(k\): \[\begin{align*}\frac{4-(-2)}{-2-1}&=\frac{k-4}{4-(-2)}\\ \frac{6}{-3}&=\frac{k-4}{6}\\ -2&=\frac{k-4}{6}\\ -12&=k-4\\ -12+4&=k\\ -8&=k \end{align*}\]
@JoStudy, to find the equation of the line, you use the point-slope formula: \[y-y_0=m(x-x_0)\] where \(m\) is the slope and \((x_0,y_0)\) is any point that you know is on the line. We've already found out that \(m=-2\) (third line in the work above). Now pick any of the three points for \((x_0,y_0)\), then plug it all into the equation.
Thanks!
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