Find the inverse Laplace transform of e^-5s/(s^2+3s+2)+e^-10s/(s(s^2+3s+2))+(1/2)/(s^2+3s+2). (I've factored the trinomial into (s+1)(s+2). But how do I find the answer? The table doesn't have e^-5s over something as the formula.)

Question

loser66 · Answer

$$\huge\frac{e^{-5s}}{s^2 +3s+2}+\frac{e^{-10s}}{s(s^2+3s+2)}+\frac{\frac{1}{2}}{s^2+3s+2}$$
right?

anonymous · Answer

Right.

loser66 · Answer

I mean $e^{-5s}$ not $e^{-5} s$, right? s is in the exponent, right?

anonymous · Answer

Right.

loser66 · Answer

ok, sweeties, let see whether I can help or not. hihihi

anonymous · Answer

You want to see the answer?

loser66 · Answer

nope, I need practice too. However, I want original problem to find out f(t)

anonymous · Answer

What's f(t)?

loser66 · Answer

inverse laplace transform of F(s)

loser66 · Answer

Don't get what I mean?
In laplace transform table, you have 2 column, the right one and the left one. The left one is respect to t , that's f(t) and correspond to them is F(s) respect to s. For example, t = 2/s^2 means |dw:1376614012021:dw|