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The sum of an integer and its reciprocal is 65/8. Find the integer
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\[x + \frac{ 1 }{ x } = \frac{ 65 }{8 }\] multiply by x and its the same idea
how do i multiply x by 65/8
Multiply both sides by 8x to get rid of the fractions.
so is it 8,1/8
\(x + \dfrac{1}{x} = \dfrac{65}{8} \) Multiply both sides by 8x: \((8x)(x + \dfrac{1}{x}) = (8x)(\dfrac{65}{8}) \) \((8x)(x) + (8x)(\dfrac{1}{x}) = (8x)(\dfrac{65}{8}) \) \((8x)(x) + (8\cancel{x})(\dfrac{1}{\cancel{x}}) = (\cancel{8}x)(\dfrac{65}{\cancel{8}}) \) \(8x^2 + 8 = 65x \) \(8x^2 - 65x + 8 = 0 \) Now either try factoring or use the quadratic formula. The answer is 8 or 1/8. You are correct.
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thanks mathstudent your the man
You're welcome.
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