Mathematics
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OpenStudy (anonymous):
Determine whether the vectors u and v are parallel, orthogonal, or neither.
u = <10, 0>, v = <0, -9>
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OpenStudy (anonymous):
Do you know about the dot product?
OpenStudy (anonymous):
Yea Sorry i was in the restroom :o
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
Then what do you get when you do the dot product?
OpenStudy (anonymous):
0?
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OpenStudy (anonymous):
Okay, so what does it mean if the dot product between two vectors is 0?
OpenStudy (anonymous):
Is it parallel?
OpenStudy (anonymous):
<0,1> and <0,1> are identical vectors... clearly they are parallel. The dot product is 1.
Thus I don't think it means that.
OpenStudy (anonymous):
so neither since there is no dot product D:
OpenStudy (anonymous):
No, the remaining options are orthogonal and neither.
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OpenStudy (anonymous):
so its orthogonal if it isnt neither?
OpenStudy (anonymous):
Im sorry i just dont know how to find these :(
OpenStudy (anonymous):
It is either orthogonal or it is neither, but we need to find out first.
OpenStudy (anonymous):
Can you think of two vectors which are orthogonal?
Do you know what orthogonal means?
OpenStudy (anonymous):
perpendicular
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OpenStudy (anonymous):
okay, so can you think of two perpendicular vectors?
OpenStudy (anonymous):
i dont know :/
OpenStudy (anonymous):
Perpendicular means the angle between to vectors is \(90^\circ\).
The dot product is equal to \(\|\mathbf v_1\|\|\mathbf v_2\|\cos\theta\)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
Where \(\theta\) is the angle between the vectors.
Is this familiar at all?
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OpenStudy (anonymous):
Yea alittle
OpenStudy (anonymous):
So what is \(\cos 90^\circ\)?
OpenStudy (anonymous):
ohhhhh Cos90=0
OpenStudy (anonymous):
so when the dot product is 0 it is perpendicular
OpenStudy (anonymous):
This is something that is supposed to be obvious.
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OpenStudy (anonymous):
Well i apologize then. Can you help me with one more?
OpenStudy (anonymous):
Let u = <-6, -2>, v = <-2, 3>. Find -3u + 2v.
OpenStudy (anonymous):
What is it?
OpenStudy (anonymous):
okay do you know how to multiply a vector by a scalar?
OpenStudy (anonymous):
i believe what i was told to do it -2(-6+-2) 2(-2,3) is that right?
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OpenStudy (anonymous):
No, that is not correct. The answer will be a vector, not a number.
OpenStudy (anonymous):
oh then no i don't know
OpenStudy (anonymous):
Can you explain how to do it? :o
OpenStudy (anonymous):
Okay, so first what is \(-3\mathbf u\) equal to?
OpenStudy (anonymous):
Hint: it is another vector.
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OpenStudy (anonymous):
\(-3\) is a scalar and \(\mathbf u\) is a vector... what happens when you multiply them?