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Mathematics 23 Online
OpenStudy (anonymous):

bout 55% of emergency room visits are unnecessary. Assuming each emergency room visit is independent. (Hints: first define the random variable X. Then write the objective of each question in terms of X.) a.If you randomly select 15 patients from those visiting the emergency department, what is the chance that all of them need to be in the emergency room? b.What is the expected number from the 15 randomly selected patients, who don’t need to be in the emergency room and what is the standard deviation of that number. @dumbcow @terenzreignz

OpenStudy (tkhunny):

Can we use a binomial approximation?

OpenStudy (anonymous):

yes we can @tkhunny

OpenStudy (dumbcow):

part 1) 45% chance visit is necessary ....chance all 15 is (.45)^15 part 2) probability is .55 , sample = 15 mean = .55*15 std dev = sqrt(.55*15*.45)

OpenStudy (anonymous):

so i only need to find .45^15. and that would be mine answer ryt?

OpenStudy (dumbcow):

yes here is a reference http://en.wikipedia.org/wiki/Binomial_distribution#Mean_and_variance

OpenStudy (anonymous):

aww..thanks soo much

OpenStudy (dumbcow):

yw

OpenStudy (anonymous):

one last question @dumbcow

OpenStudy (anonymous):

if im ask to find the probability that at least two of them need to be in the emergency room.how do i go about it?

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