Use the compound interest formulas A = Pert and A = P(1+r/n)^nt to solve. Suppose that you have $11,000 to invest. Which investment yields the greater return over 10 years: 6.25% compounded continuously or 6.3% compounded semiannually?
A. $11,000 invested at 6.25% compounded continuously over 10 years yields the greater return. B. Both investment plans yield the same return. C. $11,000 invested at 6.3% compounded semiannually over 10 years yields the greater return.
Well for your compounded continuously option, we just plug in the numbers into the A =Pe^(rt) formula. P is your principal, your initial amount, so 11,000. Rate is your percentage written as a decimal, so .0625 and time is 10. This gives us this equation: \[A = 11000e ^{(10)(.0625)}\] For the second equation, r is again written as a decimal, but is .063 this time. Time is still 10 years. N is the amount of times the interest is compounded each year. So semi-annually means twice a year, meaning n = 2. So if we plug the numbers into that formula, we get: \[A = 11000(1 + \frac{ .063 }{ 2 })^{(2)(10)}\] Now you just need to do the calculator work and see which yields the greater return :3
whats the "e" in the first equation?
e is a number kinda like pi.
2.71...
It stands for exponential function. It's the inverse of the log function. Where it actually comes from is: \[\lim_{n \rightarrow \infty}(1+\frac{ 1 }{ n })^{n}\] A calculus concept, but yeah....2.72blah blah.
well for 1. i got 335.637 without doing the e or whatever for 2. i got 1.250^81
You need to calculate the e, though. e is a number that must be calculated. You're taking e to a certain power in the first equation. For #2 you should get something like 20454.
Your calculator should have a button like \[e ^{x} \] on it somewhere
ok i see it
Yep. So we need to do e^(.625) and then multiply that result by 11000.
for one i got 20550.70553
That sounds right ^_^ Now see if you can do it correctly for the 2nd one.
i got 21887.67749
Hmm...Wonder why you're getting that. Probably the order of operations make it harder on youf or your calculator.
So let's do this piece by piece then, starting with inside of the parenthesis. So if I only do: \[1+\frac{ .063 }{ 2 }\], you should get 1.0315, correct?
yes!
Awesome. Now take that to the 20th power.
1.859450605
Multiply by 11000.
20453.95666
Much better :P So you can see which one is larger now :3
lol sorrry :p and yes the first ((:
Yeah, so there ya go :3
thankk yaa once again !
yep yep :3
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