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What are the lengths of the missing sides of a 30-60-90 Degree triangle if the longer leg of the triangle is 18 centimeters. I honestly don't understand it and would like some help
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The sides are always in the proportion of 1 Sq Root of 3 and 2
I'm assuming the "longer leg" means the square root of 3 side. So the short side = 18/sq root(3)
And the long side is 2*(18/sq root(3))
|dw:1376632554117:dw|
\[\left\{h=18 \sec (30 {}^{\circ})=12 \sqrt{3},a=18 \tan (30 {}^{\circ})=6 \sqrt{3}\right\} \]
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robtobey - Those answers you gave agree with mine.
These are the numbers I got.\[\left\{\left(12 \sqrt{3}\right)^2,\left(6 \sqrt{3}\right)^2+18^2\right\} \]\[\{432,432\} \]
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