Question

cos^2x +sinx +1=0
solve for x, please tell me how to do it

Answer 1

\[\cos^2x +sinx +1=0\]

Answer 2

i know what the answer is and it is 3pi/2

Answer 3

but i want to know how to get to it

Answer 4

cos^2 x + sin x + 1 = 0
1 - sin^2 x + sin x + 1 = 0
- sin^2 x + sin x + 2 = 0
sin^2 x - sin x - 2 = 0

Answer 5

Then use the substitution u = sin x

Answer 6

And solve for the quadratic equation, then substitute sin x back into u

Answer 7

omg thank you!!!