Question

Let A(a,0) B (0,b) c (0,0) be the vertices of a right triangle. show that the midpoint of side ab is equidistant from the three vertices

Answer 1

First plot ALL the points on a graph!
You wil get a figure like this!

Understood? :)

Answer 2

so is that the answer

Answer 3

im kinda lost

Answer 4

Do you kno wthe mid-point formula?

Answer 5

ya

Answer 6

Use that to find the Mid-point of AB

Answer 7

Now they are telling you to prove that all of their distance are the same!
Do you know the distance formula?

Answer 8

but how do i do that with no numbers
and yes

Answer 9

But you are given LETTERS [Variables]
Such as a and b!! :D
So the midpoint of AB would be (a/2,b/2)
AAnd then find the distannce from This mid-point to all the VERTICES ie. A,B,C :)

Answer 10

Let midpoint be O
Then prove by DISTANCE FORMULA
That AO = BO = OC!!
Getting me?

Answer 11

?

Answer 12

y are we using the distance formula

Answer 13

Use this formula for ALL THE points
\[\sqrt (x2 - x1)^2 + (y2- y1)^2\]

Answer 14

Because we have to prove that they are EQUIDISTANT from all points on the triangle!

Answer 15

ooooo ok

Answer 16

what do i do after this Akashdeepdeb

Answer 17

@AkashdeepDeb