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Chemistry 18 Online
OpenStudy (anonymous):

I don't get pH... Why is it the -log(H+)?

OpenStudy (rane):

you really dont get it?

OpenStudy (anonymous):

Nope.

OpenStudy (anonymous):

If you do care to explain ;D

OpenStudy (abb0t):

What is not to get? Lol To find a concentration from a pH, we use the formula: \([H_3O^+]= 10^{-pH}\) to find the pH, you take the log of both sides, you get: \(log(H_3O^+)=-pH\), but you don't want the negative on the pH side, so you multiply both sides by -1, and you get: \(-log(H_3O^+)=pH \Rightarrow pH = -log(H_3O^+)\)

OpenStudy (aaronq):

\[pH=\log\frac{ 1 }{ a _{H _{3}O ^{+}} }\] pH is the logarithm of the reciprocal of the activity (not concentration) of the hydronium ion concentration we use concentration because it's often a good estimate \[pH=\log \frac{ 1 }{ [H _{3}O ^{+}] }\] using logarithm laws we write it as: \[pH=-\log[H _{3}O ^{+}]\]

OpenStudy (anonymous):

So that's just how it is then... I guess this is my first time learning it to yeah. Thanks for the insight @aaronq and @abb0t.

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