Integrate e^x^3
\[\Huge \int\limits_{}^{} e^{x^3} dx\]
@Jonask
@oldrin.bataku @zepdrix
\[e^u=\sum_0\frac 1{n!}u^n\] \[e^{(x^3)}=\sum_0\frac 1{n!}x^{3n}\] \[\int e^{(x^3)}=\int \sum_0\frac 1{n!}x^{3n}\]
let \[u=x^3,du=3x^2\] \[\int e^{x^3}dx=\int e^u\frac{du}{3u^{\frac{2}{3}}}\]i think parts can work here
Seems so,but won't it be a little complicated?
well of course it will be... here we'll have to use the exponential integral
\[3\int\limits u^{-\frac{2}{3}}e^udu\] well we can use the gamma function here
i mean \[\frac{1}{3}\]
Well if this is too advanced then ill close this for now,I'm not taught gamma function and exponential integration,I was just trying out these questions..
yes @Jonask the incomplete gamma function: http://en.wikipedia.org/wiki/Exponential_integral#Relation_with_other_functions
\[3\int\limits u^{-\frac{2}{3}}e^udu\] well we can use the gamma function here
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