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Mathematics 12 Online
OpenStudy (anonymous):

brainfreeze: how do i remove m from this equation?

OpenStudy (anonymous):

\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m2 } = 1\]

OpenStudy (anonymous):

the equation "looks like this"

OpenStudy (anonymous):

i need only r1-r2 on that side, but my brain is malfunctioning

OpenStudy (anonymous):

anyone?

OpenStudy (asnaseer):

do you mean "how do I remove \(m_2\)" from the equation? (rather than m)

OpenStudy (anonymous):

both m's

OpenStudy (anonymous):

i don't know why this is confusing me..

OpenStudy (asnaseer):

both m's are \(m_2\) - correct?

OpenStudy (anonymous):

m1 and m2 are different

OpenStudy (anonymous):

which is why i numbered them

OpenStudy (asnaseer):

you have numbered them both as \(m_2\)

OpenStudy (anonymous):

then i made a mistake

OpenStudy (anonymous):

\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m_1 } = 1\]

OpenStudy (asnaseer):

in which case \(m_1\) and \(m_2\) are two different variables. so what do you mean when you say you want to remove m?

OpenStudy (anonymous):

i want them on the other side

OpenStudy (asnaseer):

so you want to isolate \(m_1\) and \(m_2\) on one side of the equation?

OpenStudy (anonymous):

i want to have this : \[r_1-r_2 = m_2 ...\]

OpenStudy (anonymous):

exactly

OpenStudy (asnaseer):

I don't believe you can as you will get this:\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m_1 } = 1\]therefore:\[\frac{r_1m_1-r_2m_2}{m_2m_1}=1\]therefore:\[r_1m_1-r_2m_2=m_2m_1\]

OpenStudy (asnaseer):

the best you could then do is divide both sides by, say, \(m_1\) to get:

OpenStudy (anonymous):

so..i'm not just going full-retard

OpenStudy (asnaseer):

\[r_1-r_2\frac{m_2}{m_1}=m_2\]

OpenStudy (asnaseer):

hehe - no - you are definitely not stupid my friend! :)

OpenStudy (anonymous):

phew, what a relief. But now i have to start all over again with my equation

OpenStudy (anonymous):

thanks though!

OpenStudy (asnaseer):

yw :)

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