brainfreeze: how do i remove m from this equation?
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OpenStudy (anonymous):
\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m2 } = 1\]
OpenStudy (anonymous):
the equation "looks like this"
OpenStudy (anonymous):
i need only r1-r2 on that side, but my brain is malfunctioning
OpenStudy (anonymous):
anyone?
OpenStudy (asnaseer):
do you mean "how do I remove \(m_2\)" from the equation?
(rather than m)
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OpenStudy (anonymous):
both m's
OpenStudy (anonymous):
i don't know why this is confusing me..
OpenStudy (asnaseer):
both m's are \(m_2\) - correct?
OpenStudy (anonymous):
m1 and m2 are different
OpenStudy (anonymous):
which is why i numbered them
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OpenStudy (asnaseer):
you have numbered them both as \(m_2\)
OpenStudy (anonymous):
then i made a mistake
OpenStudy (anonymous):
\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m_1 } = 1\]
OpenStudy (asnaseer):
in which case \(m_1\) and \(m_2\) are two different variables. so what do you mean when you say you want to remove m?
OpenStudy (anonymous):
i want them on the other side
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OpenStudy (asnaseer):
so you want to isolate \(m_1\) and \(m_2\) on one side of the equation?
OpenStudy (anonymous):
i want to have this : \[r_1-r_2 = m_2 ...\]
OpenStudy (anonymous):
exactly
OpenStudy (asnaseer):
I don't believe you can as you will get this:\[\frac{ r_1 }{ m_2 } - \frac{ r_2 }{ m_1 } = 1\]therefore:\[\frac{r_1m_1-r_2m_2}{m_2m_1}=1\]therefore:\[r_1m_1-r_2m_2=m_2m_1\]
OpenStudy (asnaseer):
the best you could then do is divide both sides by, say, \(m_1\) to get:
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OpenStudy (anonymous):
so..i'm not just going full-retard
OpenStudy (asnaseer):
\[r_1-r_2\frac{m_2}{m_1}=m_2\]
OpenStudy (asnaseer):
hehe - no - you are definitely not stupid my friend! :)
OpenStudy (anonymous):
phew, what a relief.
But now i have to start all over again with my equation
OpenStudy (anonymous):
thanks though!
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