Question

For the system of linear equations below, use graphing to determine in which quadrant the solution lies.

x + y = -2
-5x+6y=-30
Quadrant I

Quadrant II

Quadrant III

Quadrant IV

Answer 1

(x,y) in 1
(-x,y) in 11
(-x,-y) in111
(x,-y) in iv

Answer 2

which quadrant wold it be tho

Answer 3

First, let's graph the two lines. The simplest way to do that is to get it into slope-intercept form.\[\text{Slope-Intercept Form: } y = mx + b\]where m = slope and b = y-intercept.
So, let's do the first equation.
x + y = -2 Original Equation
y = -x - 2 Slope-Intercept form of equation
Now let's do the second one.
-5x + 6y = -30 Original Equation
6y = 5x - 30 Solving for y
y = \(\frac56\)x - 5 Slope-intercept form.
Do you know how to graph the equations?

Answer 4

Once you graph it: