Find the equation of a parabola passing through (-4, -6) whose vertex is at (-2,-4) and whose axis is parallel to the x-axis. the answer is (y+2)^2 = -2(x+2).. how to get the P given the points, vertex? Help me please. Show it to me step by step. Thank you.

Question

anonymous · Answer

r u sure its the right question and what do you mean by P

anonymous · Answer

The answer is (y+4)^2 = -2(x+2).. It wasn't (y+2)^2

anonymous · Answer

P is the distance between the vertex and the focus, and also the same (that is, equal) distance between the vertex and the directrix..

jdoe0001 · Answer

hmmm how do you know "the answer is (y+2)^2 = -2(x+2)"

anonymous · Answer

it was written in the book and I don't know how to get the answer..

jdoe0001 · Answer

something tells me you you've got the wrong answer :/

jdoe0001 · Answer

anyhow $\bf (y-k)^2=4p(x-h)$

(h, k)  = vertex point
p = distance of the focus from the vertex

anonymous · Answer

yes thats the formula..

anonymous · Answer

the vertex's given..

jdoe0001 · Answer

for an equation of say => (y+2)^2 = -2(x+2)
then the 4P = -2
solve for P to get the distance from the vertex

though notice that the (h, k) in that equation is (-2, -2)

anonymous · Answer

The answer is (y+4)^2 = -2(x+2)

anonymous · Answer

its not (y+2)^2.. sorry

jdoe0001 · Answer

ok

anonymous · Answer

How do I get p given the vertex and the points??