Question

x^2/x+3 -9/x+3 they have the same denominators but how do I subtract the top

Answer 1

\[\frac{x^2}{x+3}-\frac{9}{x+3}=\frac{x^2-9}{x+3}\] however you are not done, as you can factor the numerator and then cancel the common factor

Answer 2

how

Answer 3

\[x^2-9\] is the difference of two squares, so it factors as \[x^2-9=(x-3)(x+3)\]

Answer 4

so x-3

Answer 5

final answer

Answer 6

yes

Answer 7

awesome thanks

Answer 8

or if you want to impress your math teacher, you can write
\(x-3\) if \(x\neq- 3\)

Answer 9

yw