Question

2-sqrt[3]{x}=8

Answer 1

2-sqrt[3]{x}=8

Answer 2

\[2-\sqrt[3]{x}=8\]

Answer 3

Get the x by itself

Answer 4

8-2=−3√x
6=−3√x
-6=3√x

Answer 5

Good, now do you know how to get rid of an exponent?

Answer 6

now by taking square root on both sides
-6^3=x

Answer 7

Hold on there cowboy.

Answer 8

but the answer is 0

Answer 9

So far we have this:
\[\sqrt[3]{x}=6\]
Which is the same as
\[x^{1/3}=-6\]

How can we make that exponent 1?

Answer 10

by taking cube root on both sides

Answer 11

If we take the cubic root again, we still get a fraction. Did you mean cube both sides?

Answer 12

yes

Answer 13

sorry not cube rot just cube

Answer 14

So yea, you were right. What is -6^3?

Answer 15

it is -\[-6^{3}\]

Answer 16

Yes, do you know the final answer?

Answer 17

yes it should be 0
by by this method the answer 0 is not coming

Answer 18

Hm, weird/

Answer 19

It can't be 0 though..

Answer 20

If we plug in 0 we get this:
\[2- \sqrt[3]{0}=8\]
\[2-0=8\]
\[2 \neq 8\]