Question

solve by mathematical induction :
(6^n+2+7^2n+1)/43

Answer 1

what is there to solve?

Answer 2

\[\Large 43\left|(6^{n+2}+7^{2n+1})\right.\]

Answer 3

provide me the solution to solve this problem dude

Answer 4

Someone's in a rush....
LOL
The solution, first, show that 43 divides that stuff when n = 1.
That is...
\[\Large 6^{1+2}+7^{2(1)+1}=6^3+7^3\]

Answer 5

i want solution after substituting n=k dude

Answer 6

Well, we assume that 43 does indeed divide \[\Large 6^{k+2}+7^{2k+1}\]

Answer 7

Now all that's left to find is whether or not it divides the stuff when n = k+1

Answer 8

thats the solution i needed

Answer 9

\[\Large 6^{k+1+2}+7^{2(k+1)+1}=6^{k+3}+7^{2k+3}\]

Answer 10

that's a stomper...

Answer 11

i want the solution of proving that it is equal dude

Answer 12

dude end the solution

Answer 13

I'm still thinking :)

Answer 14

k dude try to post after completing the solution

Answer 15

besides, you should be throwing in your own ideas :P

Answer 16

Let's try factoring a bit
\[\Large 6\cdot 6^{k+2}+7^2\cdot 7^{2k+1}\]
should be easy from here :)

Answer 17

still blank? ^.^

Answer 18

yes

Answer 19

I uploaded the solution here, but first, I want to see your work :)
http://www.megafileupload.com/en/file/442537/proof-43-divides-docx.html

Answer 20

weird...