Question

sin 2x-sin 2y/cos 2y=cot(x+y)

Answer 1

Is it meant to sin 2x or sin^2x?

Answer 2

it is sin2x

Answer 3

And is the whole term over cos 2y?

Answer 4

no

Answer 5

I don't know!
Tag some people!

Answer 6

i don't get it. do we need to prove that or bring out a relation between x and y?

Answer 7

prove that

Answer 8

@amistre64

Answer 9

sin 2x - sin 2y/cos 2y = cot(x+y)

2sin(x)cos(x) - 2sin(y)cos(y)/[cos^2(y)-sin^2(y)] = cos(x+y)/sin(x+y)

... = [cos(x)cos(y) - sin(x)sin(y)]/[sin(x)cos(y)+sin(y)cos(x)]

thats what i got for a start

Answer 10

i can never recall the tangent stuff ....

Answer 11

as is, its not an identity, so its has to do with finding suitable values at best

Answer 12

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