Question

Tricky Algebra 2 problem. :/ It's solving for extraneous solutions. Take a look please?

Answer 1

\[9\left| 9-8x \right| = 2x + 3\]

Answer 2

So far I have
\[9 - 8x = \frac{ 2 }{ 9}x + \frac{ 1 }{ 3}\]

Answer 3

so your equation is good.. find x.
but there is another equation that satisfies theequation in the question

Answer 4

would i subtract 9 from both sides? and i will do the other equation too :)

Answer 5

so we take all the terms without x to one side and the terms with x to the other.
you can subtract 9 from both sides and then subtract also 2x/9 from both sides.

Answer 6

So after subtracting 9 from both sides I get \[8x = \frac{ 2 }{ 9}x -\frac{ 26 }{ 3}\]

Answer 7

i wrote:
|x| = a
gives two options :
x=a
and
x=-a

there should be an "or" instead of the "and" between the solutions :)

Answer 8

then i would subtract 2/9x from both sides. right?

Answer 9

what happened to the - before the 8x ?

Answer 10

9|9−8x|=2x+3
|9−8x|=2x+3/9
9−8x=2x+3/9 or 9−8x=-(2x+3/9)
9(9−8x)=2x+3 or 9(9−8x)=-(2x+3)
81-72x=2x+3 or 81-72x=-2x-3
81-3=2x+72x or 81+3=-2x+72x
78=74x or 84=70x
x=78/74 or x=84/70
x=39/37 or x=6/5

Answer 11

oops almost left that out!

Answer 12

@Nurali why did you solve it ? you see that she is trying!

Answer 13

thank you both for helping me :)

Answer 14

My Pleasure.