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OpenStudy (uri):
multiply 1st eq with 3
OpenStudy (anonymous):
wait what?
OpenStudy (uri):
Yes
to get y value equal with 2nd eq
OpenStudy (uri):
3x-6y=-18
4x+6y=4
======
7x=-14
x=-14/7
x=-2
OpenStudy (anonymous):
where did you get 3x?
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OpenStudy (uri):
we multiply the whole first eq with 3
OpenStudy (anonymous):
Where did you get the three at?
OpenStudy (uri):
Ah we have to make y values of both eq same with different signs so yeah...3 x -2 =-6
OpenStudy (anonymous):
OK! So I have to solve the first equation
x-2y=-6 first!
OpenStudy (anonymous):
Thanks uri! (again :P)
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OpenStudy (uri):
yw find y now
OpenStudy (anonymous):
OK x=-2
using
3x-6y=-18
3(-2)-6y=-18
-6-6y=-18
-6+-6-6y=-18+-6
-6y=-24
-24/-6=
y=4
OpenStudy (anonymous):
wait that doesn't look right
OpenStudy (uri):
No use the original 2nd eq
OpenStudy (anonymous):
OK so
4(-2)+6y=4
-8x+6y=4
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OpenStudy (anonymous):
I'm solving for y so I put 0 in the place of 6
-8x=4
-8x=4
OpenStudy (anonymous):
-8/4=
-2
OpenStudy (anonymous):
y=-2
OpenStudy (anonymous):
wait -8x=4 isn't -8/4
it's 4/-8
-.5
OpenStudy (anonymous):
NO! crazy liner equations >.<
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OpenStudy (anonymous):
4x+6y=-6
x=-2
4(-2)-2y=-6
-8x-2y=-6
OpenStudy (anonymous):
wait i mean -8x-2y=-4
OpenStudy (anonymous):
typo -8x-2y=4
OpenStudy (anonymous):
am I right so far?
OpenStudy (anonymous):
here is an alternative method
\[x-2y=-6\\ 4x+6y=4 \]
the first equation is the same as
\[x=2y-6\] so you can replace \(x\) in the second equation by \(2y-6\) with careful use of parentheses and solve
\[4(2y-6)+6y=4\] for \(y\)
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