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Mathematics 12 Online
OpenStudy (anonymous):

x-2y=-6 4x+6y=4

OpenStudy (uri):

multiply 1st eq with 3

OpenStudy (anonymous):

wait what?

OpenStudy (uri):

Yes to get y value equal with 2nd eq

OpenStudy (uri):

3x-6y=-18 4x+6y=4 ====== 7x=-14 x=-14/7 x=-2

OpenStudy (anonymous):

where did you get 3x?

OpenStudy (uri):

we multiply the whole first eq with 3

OpenStudy (anonymous):

Where did you get the three at?

OpenStudy (uri):

Ah we have to make y values of both eq same with different signs so yeah...3 x -2 =-6

OpenStudy (anonymous):

OK! So I have to solve the first equation x-2y=-6 first!

OpenStudy (anonymous):

Thanks uri! (again :P)

OpenStudy (uri):

yw find y now

OpenStudy (anonymous):

OK x=-2 using 3x-6y=-18 3(-2)-6y=-18 -6-6y=-18 -6+-6-6y=-18+-6 -6y=-24 -24/-6= y=4

OpenStudy (anonymous):

wait that doesn't look right

OpenStudy (uri):

No use the original 2nd eq

OpenStudy (anonymous):

OK so 4(-2)+6y=4 -8x+6y=4

OpenStudy (anonymous):

I'm solving for y so I put 0 in the place of 6 -8x=4 -8x=4

OpenStudy (anonymous):

-8/4= -2

OpenStudy (anonymous):

y=-2

OpenStudy (anonymous):

wait -8x=4 isn't -8/4 it's 4/-8 -.5

OpenStudy (anonymous):

NO! crazy liner equations >.<

OpenStudy (anonymous):

4x+6y=-6 x=-2 4(-2)-2y=-6 -8x-2y=-6

OpenStudy (anonymous):

wait i mean -8x-2y=-4

OpenStudy (anonymous):

typo -8x-2y=4

OpenStudy (anonymous):

am I right so far?

OpenStudy (anonymous):

here is an alternative method \[x-2y=-6\\ 4x+6y=4 \] the first equation is the same as \[x=2y-6\] so you can replace \(x\) in the second equation by \(2y-6\) with careful use of parentheses and solve \[4(2y-6)+6y=4\] for \(y\)

OpenStudy (anonymous):

Thanks @satellite73!

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