Which two values of x roots are polynomial below 5x^2+5x-1

Question

anonymous · Answer

$$A. x=\frac{-8\pm \sqrt{28} }{ 6 }$$

anonymous · Answer

B.$$x=\frac{ 5\pm \sqrt{5} }{ 10}$$

anonymous · Answer

C.$$x=\frac{ 5\pm \sqrt{45} }{ 20 }$$

hero · Answer

Use the quad formula

anonymous · Answer

the ? doesnt mean solve using the quadratic formula right because i solved and i got something different

anonymous · Answer

i did but my answer doesnt match none of this

anonymous · Answer

oh snaps damn srewed up i got B xD

anonymous · Answer

i mean c

hero · Answer

So you figured it out now?

anonymous · Answer

nevermin i got $$x=\frac{ -5\pm \sqrt{45} }{ 10}$$

mathstudent55 · Answer

$5x^2+5x-1 = 0$

$ x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 5, b = 5, and c = -1, so

$ x = \dfrac{-5 \pm \sqrt{5^2 - 4(5)(-1)}}{2(5)} $

$ x = \dfrac{-5 \pm \sqrt{25 + 20}}{10} $

$ x = \dfrac{-5 \pm \sqrt{45}}{10} $

$ x = \dfrac{-5 \pm 3\sqrt{5}}{10} $

None of the answers are correct.

anonymous · Answer

wait the 1 is +

anonymous · Answer

the answer is B sorry guys

mathstudent55 · Answer

B has +5 instead of -5. Also, B has sqrt(5), not sqrt(45).
Look art my step before the last one and compare it to B.

anonymous · Answer

it is b because my equation is suppose to look like this 5x^2-5x+1

mathstudent55 · Answer

In other words, we just wasted 20 minutes solving the wrong problem and arguing about how the solution choices are all wrong.

hero · Answer

Technically, even though that is true to an extent, he was still able to figure out his own mistake and figure out the correct answer to the correct problem, so it wasn't a total waste.