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Use the graph of log\/5x to obtain the graph of f(x) = 2 + log\/5x.
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Given the graph of y=f(x), the graph of y=f(x)+a is a vertical shift of a units up (or down |a| units if a<0). Make sense? So you are looking for the graph that takes the original graph and "slides it up" 2 units.
And don't for get that any function of the form \[y=\log_{b}x \] has a vertical asymptote at the y-axis, and an x-intercept at x=1.
I think its C
Why? Where is the x-intercept on C? Where should it be for the function you are looking for? Remember - if you shift up a function 2 units, it will not change the vertical asymptote but it WILL shift up the x-intercept.
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In that case, it has to be A.
Very good. :)
Thanks
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