Find the lateral area for the prism.
@surjithayer
I wonder which the base is, the rectangular or the triangular depending on which the base is, then we'd know which are the lateral sides
I think I have half of the equation correct
because if we skip the triangles, we really only have 3 rectangles as sides
Oh, I see what you mean
The end product is suppose to fit into an equation such as this: \[?+?\sqrt{3}\]
one side is 6, one side is 4 both are sides in a right triangle, meaning the other side is NOT 6, but longer
sorry, disregard the "3" I put in the equation
wouldn't the base be 4 times the square root of 3?
hmm well if all they want is the lateral area, you don't need the base
and if the base is the triangle there at the bottom then is just adding 3 rectangles
Oh, sorry. I was thinking of total area
LA= ph
so looking at the triangle, it has a side of 4 and a side of 6, is a right triangle so a = 4, b = 6 \(\bf c^2 = a^2 + b^2 \implies c = \sqrt{a^2 + b^2} \implies c = \sqrt{4^2 + 6^2} \)
\(\bf c = 4\sqrt{13}\) so you have 1 rectangle of 4 x 8 and one of 8 x 6 and another rectangle of \(\ 8 \times 4\sqrt{13}\)
hmmm shoot
\(\bf c = 2\sqrt{13}\) so you have 1 rectangle of 4 x 8 and one of 8 x 6 and another rectangle of \( \ 8 \times 2\sqrt{13}\)
hmm, something is not ... working well
ok, yes, I thought I had a typo,
I still don't understand how to calculate the LA by using the measurements of each of those though
do I calculate the perimeter of each individual one, add them, then multiply by 8??
well, the rectangles are the SIDES, or LATERALS, you get their Area, add them up, and that's the lateral area
ok, thank you! so I just need to calculate the area of the rectangles?:)
yes
alrighty! thank you!
yw
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