Find the volume for the regular pyramid.
@surjithayer
@Ahmad1
the volume= 1/3*the area of the base* height right or it's the slant height?
yes that is right
okay , now we have to evaluate the area of this polygon, do u remember a direct rule I should try to find it by deviding it into three triangles?
or I should**
Since you just need to find the area of the base couldn't you just evaluate that and add it into the formula?
lol yes I can , but I forgot what's the rule the area of the polygon
oh! im sorry! haha the rule for area of a pentagon is A=\[\frac{ 1 }{ 2 }ap\]
is this what you needed?
\[\frac{ 1 }{ 2 }apothem timesperimeter\]
that's "apothem times perimeter"
yes thank you, but I still don't understand what does apothem mean lol anyways you certainly do so we have the area of the pentagon
The apothem of a regular polygon is a line segment from the center to the midpoint of one of its sides.
Equivalently, it is the line drawn from the center of the polygon that is perpendicular to one of its sides. The word "apothem" can also refer to the length of that line segment. Regular polygons are the only polygons that have apothems. Because of this, all the apothems in a polygon will be congruent and have the same length.
I think I found it!
i got \[3\sqrt{8}\]
okay thank you so much , looks like im getting more benifet than you I tried many time to draw but I couldn't I accurately make one
sure?
haha! its alright! but thank you for your help!:)
oh wait that's not the right answer.... haha!
so I think now a clever guy like you can figure the height himself. right :P
oops! we did not sub in the equation of the volume yet @mollsy
also you did not find the height
isn't the height also considered the apothem?
or is it considered the slant height?
I don't think so , I cant draw any figure to proof!! it's kinda hard with these tools can you imagine the right triangle formed by the slant height, apothom,and height ?
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this where you can get the height ;)
could i figure out the altitude by using the Pythagorean theorem?
if i subbed in \[h ^{2}\]
lol, that's what Im trying to say
so that it is a\[a ^{2}+b ^{2}=c ^{2}\]
\[h^2=6^2-(3\sqrt{8})^2\]
oh... haha
but this looks impossible to me :\
yeah i'll try solving it myself and if i don't get i'll just come back!
it's the apothom which is wrong my friend it must be smaller , you try and I'll try to find it and tell
okay
i got \[144\sqrt{3}\] but somehow i don't think its right. haha
OMG! it's very impossible
can you tell me please what's th measure of the angles?
it's given by some rule as I remember
or maybe it is 48\[\sqrt{3}\]
i mean 48*square root 3
i'll try that
I wish I can come next to you and see how you get these results :P
haha i'll just skip this problem and move to the next
no no I actually got the apothhom in terms of the angle it's \[4\sin(\theta/2)\] but still need to know theta! look like u don't study very well my friend :P just go back to the book and look for the rule of the angle of the regular polygon I'm sure you well get it
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