Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6). y = one thirdx + 7 y = −3x + 3 y = one thirdx + 3 y = −3x + 7
@gypsy1274 I know I have to use the same, y-y1 =m (x-x1) process
Am I right?
The only difference between this one and the last one is the slope. Perpendicular requires a negative reciprocal. Parallel has the same slope.
Yes, you are right.
So this one is still Y- (-1) = 1/3 (x-6)?
(x,y) (-1,6) Do you see your mistake?
And this question is asking for a parallel line so the slope will be the same as the given line.
Aw poop. I do, I am sorry.
No problem. If at first you don't succeed, try, try again.
Y-6= 1/3 (x - -1)?
Every mistake provides an opportunity to learn.
Almost. What is the slope of the original equation?
12?
y=mx+b m=slope
y=-3x+12
So I solve from there? Or...?
Find the correct slope.
What is the slope of the original line?
Wait! I think I seen this problem in an example from the lesson!
I am going to go out on a limb here and say it is Y= -3X =3?
Do you understand how to do the problem?
Getting the correct answer without understanding cheats you of learning.
That was my photographic memory speaking. But not really, so I would really appreciate if you explained.
Start by finding the slope of the original line. y=-3x+12 y=mx+b m=slope
I am stumped on how to find the slope, what numbers do I include, and how do I get them?
You do not need to do anything to it, just find it. Re-read the previous post and see if you can figure it out.
What do you think?
So can I add1? seeing that is parallel?
Have you identified the slope of the original equation?
No, not really, slope always gets me. I know the way I need to set it up, but I never know HOW someone gets it. What do they do to get that number.
You don't do anything to it. Just find it. m=slope. m is the coefficient of the x term.
Is it making sense yet?
So the slope is 12, or -3?
I am thinking -3.
The slope is -3.
Ok, so we set it up like y-6 = -3 (x- -1)
A parallel line has the same slope. So plug the point values and the slope in to the point-slope formula.
Ok, so we set it up like y-6 = -3 (x- -1)
Yes. Then solve for y.
Ok, so when we solve for Y, we distribute -3?
yes.
which leaves us with y- 6= -3x -3?
yes. One more step.
We get rid of six? By subtracting on both sides?
Yes.
So then we have y= -3x + 3!
Yes. You got it! \[\Huge \text{(^◡^ )}\]
Yay! ok, I am going to try the next problem myself, then post it here for you to check, if I get it right, then Woo! If not ,then you can explain :D?
Sounds like a great plan.
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