Question

HELP ME PLEASE. find the equation of a parabola whose vertex is on x= -2, latus rectum 8, passing through (-7/8, 4) and whose axis is parallel to the x-axis. the answers are (y-1)^2 = 8(x+2) and (y-7)^2 = 8(x+2). Show it to me step by step. tHANK YOU :)

Answer 1

NO

Answer 2

ok fine lets do it

Answer 3

rectum (god help me) is 8 so we know where the 8 comes from in the answer right?

Answer 4

we also know it is parallel to the \(x\) axis so the \(y\) is squared

Answer 5

im so sorry its just that were having an examination today..

Answer 6

and since the vertex is on \(x=-2\) we got that the \(x\) coordinate of the vertex is \(-2\)

Answer 7

put it all together and you get
\[(y-k)^2=8(x+2)\]

Answer 8

lol no need to be sorry
pretty much like the last one right? put all the facts together, then solve for the number you do not know

Answer 9

yes yes the last one..

Answer 10

put \(x=-\frac{7}{8}\) and \(y=4\) and solve for \(k\)

Answer 11

you are going to get a quadratic, which is why there are two solutions

Answer 12

\[(y-k)^2=8(x+2)\]
\[(4-k)^2=8(-\frac{7}{8}+2)\]

Answer 13

where m i going to put the points? in the formula? YES. aaah yes. :)

Answer 14

yes
all these that you had pretty much seemed to work the same way

Answer 15

okay thank you so much!! sorry for disturbing you :) @satellite73

Answer 16

put together the facts to get as much of the equation as you can, then plug in the numbers to get the ones you do not know

Answer 17

got it now!! :) thanks again! goodnight!!

Answer 18

not disturbing me
if i didn't want to answer, i could ignore the question
good luck on your exam

Answer 19

Thanks!!

Answer 20

yw