Question

x2-17x+30

Answer 1

Factor, I presume?

So you need factors of +30 that sum to -17.... that is, for what m,n does mn=30 AND m+n=-17?

Once you have that, it should be pretty easy to fill in:
(x+?)(x+?)

And don't forget to ALWAYS CHECK FACTORING WITH MULTIPLICATION!!

Answer 2

Tnx!but I need answer -17 in the factor of 30

Answer 3

Can u tell me how to put photos in, it'll be better understood by that

Answer 4

I don't understand your question....

Think about the factors of 30. There aren't that many.
6&5, -6&(-5)
3&10, -3&(-10)
2&15, -2&(-15)
1&30, -1&(-30)

What factor pair has a sum of -17?

Answer 5

I know the answer but don't know how to put photos, there are roots applied here, can u tell me how to upload photos?

Answer 6

I have never added a photo, but I presume you click the "attach file" button below and then attach it?

Answer 7

this is a test....

Answer 8

Just wait a sec

Answer 9

This is quadratic factoring like x2+x-20(x+5)(x-4)

Answer 10

OK, that's how you can solve
\[x^2-17+30=0\]using the quadratic formula. (You're original post did not have an equation, just the trinomial - so I thought you just had to factor.)

To solve a quadratic, there are a few methods you can use. You can ALWAYS use the quadratic formula to find the solutions.

Sometimes, you can just use factoring to find the solutions... which is usually easier than the QF. So:\[x^2-17+30=0\]\[(x-15)(x-2)=0\]So either x-15=0 or x-2=0.
So either x=15 or x=2.

Answer 11

But if you are required to use the Quadratic Formula, then do so. It's just plug & chug:
\[x=\frac{ -b\pm \sqrt{b^2-4ac} }{2a}\]Plug in a,b, and c and you get your solutions (may be complex, if you are allowing those).

Answer 12

if the value under the roots is less than zero the sol.s are'nt real, if equal to zero only one sol, and if more than zero, it has two reals sol.s

Answer 13

OK wait a sec. I just realized that the image I was responding to wasn't posted by the original question poster. So I'm still not sure what the question is. lol

Answer 14

hey debbieG, are u good at trigonometry, i have this question here, http://openstudy.com/study#/updates/521350a7e4b0450ed75da63c

Answer 15

Please help me to answer this x2-7x+12/x2-18x+32/x2-13x+42/x2-12+36

Answer 16

@Ortiaga , what is the question?? Are you factoring these? I explained how to do that above.

Answer 17

\[x^2-7x+12\]Look for factor pairs of +12 that sum to -7 and you come up with -3, -4 since (-3)(-4)=12 and (-3)+(-4)=-7. So you need:

(x-3)(x-4)

Check the factoring by multiplying (FOIL) and verify that the product is the original binomial you started with.

Now you try the others.

Answer 18

Thank you debbieg

Answer 19

I been confuse how I'm gonna get it the -7 if the sign is different!

Answer 20

debbieg in quadratic factoring if the given sign is not same it means subtraction!