Question

solve

Answer 1

P(r,b,w) + P(r,w,b) + P(b,w,r) + P(b,r,w) .. should be 6 of these

Answer 2

6 * (5.3.2)/(10.9.8) sounds about right

Answer 3

The number of ways of choosing one ball of each color in a random sample of 3 is
\[5\times3\times2\]
The total number of ways of choosing 3 balls at random out of 10 balls is 10C3.
The required probability is given by
\[P(3\ different\ colored\ balls)=\frac{5\times3\times2}{\frac{10!}{3!7!}}=you\ can\ calculate\]

Answer 4

im assuming without replacement ...

Answer 5

1/4

Answer 6

Your result is correct!