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Find the product of the complex number and it's conjugate; 7-6t
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hint: (a+bi)*(a-bi) = a^2 + b^2
7-6t doesn't look very complex per se
I'm sorry I really don't understand
the number is 7-6i right?
Yes, but how do I get a product from that
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the conjugate is 7+6i
multiply the two numbers using the rule I posted above
or you can expand it out the long way
How do I get a product withput an = sign?
in this case, a = 7 and b = 6
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so... (a+bi)*(a-bi) = a^2 + b^2 (7+6i)*(7-6i) = 7^2 + 6^2 (7+6i)*(7-6i) = ???
THANK YOU SO MUCH
yw
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