can anyone solve this y"-(2/x)y'+(1+2/(x^2))y=xe^x
seems doable ...
im thinking series ....
no series
why not?
You can use laplace transform.
might as well be asking: can any one open this door? sure. um, but without using your hands? ....
LOL!
u see u have two hands use the other one
without using any methods known to man ... solve it :)
laplace requires intial conditions i believe
u mean the only method is using series?
avril lavigne, aren't you a singer? Why are you taking differential equaitons?
You can use reduction of order to reduce them to constant coefficients if i remember correctly.
variation of parameters ... a wronskian .... stuff like that maybe
I myself think it must be some kind of substitution! looks like one
to use wronskian I need at least one solution
\[let~y=\sum_0c_n~x^n\] :) thats a substitution
http://tutorial.math.lamar.edu/Classes/DE/ReductionofOrder.aspx that's the method i was talking about. reducing it to constant coeff. but there is another method that you don't need to reduce them to constant coeff, but instead a similar method to using annihilators. But i have to go, hope this helps!
you can develop one solution from the homogenous and then work it into the wronskian ... by chance
that's not a substitution! thats an answer u gave! I don't know how?
:)
what do u mean by chance?
took diff eq three years ago, don't remember much, bump for review
i mean that if you can solve the homogenous then you have one of the solutions to apply for the wronskian; but that rests on the ability to determine the homogenous solution to start with
well that is the primary problem! the rest is pretty simple
reducing to constant coefficient must be the solution but for that I need a good substitution.
You could find the auxiliary equation of the left hand side, then use it to find a general solution (ie complementary function) Then find a particular solution to rhs and add them together
well u can't find an exact solution to the right handside without solving \[y_{g}\] sarahusher
u know any general substitutions for reducing
Join our real-time social learning platform and learn together with your friends!