Question

(2^7*2^8)/2^3

Answer 1

So far I have \[\frac{ 2^{7}*2^{8} }{ 2^{3}}\]
\[2^{7}*2^{8} \rightarrow 2^{15}\]

Answer 2

\[\frac{ 2^{15} }{2^{3} }\]

Answer 3

Correct. You used this rule in the numerator.
\( a ^m \times a^n = a^{m + n} \).

Answer 4

\[2^{15-3}=2\]

Answer 5

Sorry 2^12

Answer 6

Is that correct?

Answer 7

Now you need this rule for the fraction:

\(\dfrac{a^m}{a^n} = a^{m - n} \)

Answer 8

2^12.
You are correct.

Answer 9

Thanks!

Answer 10

wlcm