Mathematics
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OpenStudy (amtran_bus):
Converse of pythagorean theorem help!
***see attachment problem***
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OpenStudy (amtran_bus):
OpenStudy (zzr0ck3r):
do you know how to find the distance between two points?
OpenStudy (amtran_bus):
Sure, just the distance formula.
OpenStudy (zzr0ck3r):
so find the distance of each side of the triangle
OpenStudy (zzr0ck3r):
or the length of each side of the triangle...
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OpenStudy (amtran_bus):
Is point A at 31/2, 3/12?
OpenStudy (amtran_bus):
or 3,3?
OpenStudy (zzr0ck3r):
3,3
OpenStudy (zzr0ck3r):
at least that's what it looks like to me
OpenStudy (amtran_bus):
I agree
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OpenStudy (amtran_bus):
so d(A,B) is sqrt 10?
OpenStudy (amtran_bus):
and d(B,C) is sqrt 40?
and d(A,C) is sqrt 50?
@zzr0ck3r
OpenStudy (zzr0ck3r):
d(a,b) is right
one sec
OpenStudy (amtran_bus):
Thanks, zz0ck3r for helping me.
OpenStudy (zzr0ck3r):
yep
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OpenStudy (zzr0ck3r):
all good so far
OpenStudy (amtran_bus):
Nice
OpenStudy (zzr0ck3r):
now make sure that d(c,b)^2+d(b,a)^2 = d(a,c)^2
OpenStudy (zzr0ck3r):
and it does....
for the next part
\[area=\frac{1}{2}*b*h = \frac{1}{2}*d(C,B)*d(B,A) \]
OpenStudy (amtran_bus):
That is 10.
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OpenStudy (zzr0ck3r):
correct
OpenStudy (amtran_bus):
Nice! So for the last part, the first drop down menu gives the choice A or B and the second also A or B.
OpenStudy (amtran_bus):
So I think the first one is B and the next is A.
OpenStudy (amtran_bus):
@zzr0ck3r
OpenStudy (zzr0ck3r):
yes
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OpenStudy (amtran_bus):
Thanks!
OpenStudy (zzr0ck3r):
np, nice work.
OpenStudy (amtran_bus):
Thanks.