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Mathematics 23 Online
OpenStudy (amtran_bus):

Converse of pythagorean theorem help! ***see attachment problem***

OpenStudy (amtran_bus):

OpenStudy (zzr0ck3r):

do you know how to find the distance between two points?

OpenStudy (amtran_bus):

Sure, just the distance formula.

OpenStudy (zzr0ck3r):

so find the distance of each side of the triangle

OpenStudy (zzr0ck3r):

or the length of each side of the triangle...

OpenStudy (amtran_bus):

Is point A at 31/2, 3/12?

OpenStudy (amtran_bus):

or 3,3?

OpenStudy (zzr0ck3r):

3,3

OpenStudy (zzr0ck3r):

at least that's what it looks like to me

OpenStudy (amtran_bus):

I agree

OpenStudy (amtran_bus):

so d(A,B) is sqrt 10?

OpenStudy (amtran_bus):

and d(B,C) is sqrt 40? and d(A,C) is sqrt 50? @zzr0ck3r

OpenStudy (zzr0ck3r):

d(a,b) is right one sec

OpenStudy (amtran_bus):

Thanks, zz0ck3r for helping me.

OpenStudy (zzr0ck3r):

yep

OpenStudy (zzr0ck3r):

all good so far

OpenStudy (amtran_bus):

Nice

OpenStudy (zzr0ck3r):

now make sure that d(c,b)^2+d(b,a)^2 = d(a,c)^2

OpenStudy (zzr0ck3r):

and it does.... for the next part \[area=\frac{1}{2}*b*h = \frac{1}{2}*d(C,B)*d(B,A) \]

OpenStudy (amtran_bus):

That is 10.

OpenStudy (zzr0ck3r):

correct

OpenStudy (amtran_bus):

Nice! So for the last part, the first drop down menu gives the choice A or B and the second also A or B.

OpenStudy (amtran_bus):

So I think the first one is B and the next is A.

OpenStudy (amtran_bus):

@zzr0ck3r

OpenStudy (zzr0ck3r):

yes

OpenStudy (amtran_bus):

Thanks!

OpenStudy (zzr0ck3r):

np, nice work.

OpenStudy (amtran_bus):

Thanks.

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