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Mathematics 15 Online
OpenStudy (anonymous):

Simplify the expression.

OpenStudy (mathstudent55):

Use the square of a binomial first.

OpenStudy (anonymous):

can you simplify it for me?

OpenStudy (mathstudent55):

Then use an identity to simplify it further.

OpenStudy (anonymous):

How would I find the max and min values from it ?

OpenStudy (anonymous):

OpenStudy (anonymous):

I thought it'd be A

OpenStudy (mathstudent55):

How can I know? I don't see the expression any longer.

OpenStudy (anonymous):

So I simplified this .. is it correct? y= 2cos(-1/2(x-180^@))-3

OpenStudy (anonymous):

Oh Im sorry I sent a screen shot

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

OpenStudy (mathstudent55):

The screen shot is not the problem. The problem is I don't see the original question any more. What are you trying to simplify? Where did it go?

OpenStudy (anonymous):

no the screen shot is my question lol

OpenStudy (anonymous):

ok I am simplifying This: y= 2cos(-1/2x + 90^@) -3

OpenStudy (anonymous):

give me the period, amplitude, max/min values, range, domain, horizontal phase shift and vertical displacement.

OpenStudy (mathstudent55):

@cupcakezz If you have a question, start a post and ask the question. Don't ask your question in the middle of someone else's question.

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

so do i expand it of just distribute the exponent?

OpenStudy (anonymous):

*or

OpenStudy (mathstudent55):

@isabel_xxvi For the third time, I can't help you with a problem that I can't see. What happened to the expression you want to simplify? It's not longer there. I can't see it.

OpenStudy (anonymous):

it's the same as the one in the picture (cot x + csc x)^2

OpenStudy (anonymous):

how do I start a post ?

OpenStudy (mathstudent55):

Ok, I see it. Sorry. You had it there, and I didn't know.

OpenStudy (mathstudent55):

\( (\csc x + \cot x)^2 \) Square the binomial: \(\csc^2 x + 2\csc x \cot x + \cot^2 x\)

OpenStudy (mathstudent55):

\(=1 + \cot^2 x + 2 \csc x \cot x + \cot^2 x \) \(=1 + 2\cot^2 x + 2 \csc x \cot x\)

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