Question

Prove the Identity:
1+sinx-cos^2x/1+sinx=sinx

Answer 1

\[\frac{ 1+sinx+\sin^2x-1 }{sinx+1 } \]
one cancel with minus one , take sin(x) as a common factor and see what happens

Answer 2

\[\frac{1+\sin x-\cos^2x}{1+\sin x}=\sin x\]
for those wondering

Answer 3

...........................

Answer 4

this will help you simplify it:
\[\cos2x = \cos^2x-\sin^2x\]

Answer 5

Ummmmmmmm I don't understand what you are getting at. I just need to get the left to equal the right........

Answer 6

didn't you get my point ?

Answer 7

No....I don't understand.

Answer 8

you have sin^x+cos^x=1 ,so cos^x=1-sin^x , now we sub in the LHS\[\frac{ 1+sinx+\sin^2x-1 }{ sinx+1 } \rightarrow \frac{ sinx (sinx+1) }{ (sinx+1) }=sinx\]

Answer 9

Nevermind.................

Answer 10

just tell me what's the problem :(

Answer 11

You just didn't explain it clear enough.........I got my question answered though, thanks.

Answer 12

I'm sorry I've just sen it ... good luck

Answer 13

thanks

Answer 14

Dear awesomelady2, you've go to know the rules about the trigonometric functions, the proof is clear enough, I would recommend you to see the geometrical explanations of those proofs.

Answer 15

I'm just really stressed, that's all. I have a /GIANT/ test tomorrow